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An object starting from rest undergoes an acceleration of 8ms ^(-2)for 10 second. Find (a) the speed (b) the distance travelled. |
Answer» Solution :`u =0, a =8 MS ^(-2), t =10` second `(a) V =u +at` `=0 + 8 ms ^(-2) xx 10s ` `= 80 ms ^(-1) ""..(1)` ` (b) s = ut + (1)/(2) at ^(2)` ` = 0 xx 10 + (1)/(2) xx 8 ms ^(-2) xx (10 s ) ^(2) ` `=0 + 4 xx 100 m = 400 m ""...(2)` The speed of the OBJECT is `80 ms ^(-1),` the distance travelled by the object is 400 m. |
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