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An oil drop has ` 8.01 xx 10^(-19) C` charg .Calculate the number of electrons in this drop. |
Answer» Correct Answer - 5 Charge on lil drop ` = 8. 01 xx 10^(-19) C` ` :. 1 . 602 xx 10^(-19 ) C` is charge on one electron ` :. 8. 01 xx 10^(-19) C` charge on ` = ( 8. 01 xx 10^(-19))/(1. 602 xx 10^(-19)) = 5` electrons . |
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