InterviewSolution
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InterviewSolution
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As what temperature the speed of sound in air will because double of its value at `27^(@)`?A. `54^(@)C`B. `627^(@)C`C. `927^(@)C`D. `327^(@)C` |
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Answer» Correct Answer - c Speed of sound is given by `v = sqrt((gamma P)/(A))` ..(1) where rho is ratio of specific heat P is pressure and d is density Also `PV = RT,` where `V` is volume R gas constant and T is temperature `P (m)/(d) = RT` `rArr (P)/(d) = (RT)/(m)` putting the value in Eqs (i) we get `v = sqrt((gamma RT)/(m))` Given ` v_(1) = v, T_(1) = 27 + 273= 330 K` `v_(2) = 2v` `:. (v_(1))/(v_(2)) = (v)/(2v) = sqrt((T_(1))/(T_(2))) = sqrt((300)/(T_(2)))` `rArr T_(2) = 4 xx 300 = 1200 K` `rArr T_(2) = (1200 - 273)^(@)C = 927^(@)C ` |
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