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Assertion : `._(11)^(22)Na` emits a positive giving `._(12)^(22)Mg` Reaosn : In `beta` emission neutron is transformed into proton |
Answer» Correct Answer - D `._(11)Na^(22) rarr ._(12)Mg^(22) + ._(-1)beta^(0)` Thus this change involves a `beta`-particle emission and not a positron. Also, proton emission converts proton into neutron as : `._(1)P^(1) rarr ._(0)n^(1) + ._(+1)beta^(0)` |
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