1.

Assertion : `._(11)^(22)Na` emits a positive giving `._(12)^(22)Mg` Reaosn : In `beta` emission neutron is transformed into proton

Answer» Correct Answer - D
`._(11)Na^(22) rarr ._(12)Mg^(22) + ._(-1)beta^(0)`
Thus this change involves a `beta`-particle emission and not a positron. Also, proton emission converts proton into neutron as : `._(1)P^(1) rarr ._(0)n^(1) + ._(+1)beta^(0)`


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