1.

Assume a spring extend by “d” due to some load. Let “F” be the spring force and “k’ the spring constant. Then, the potential energy stored is _____(a) 2d/F^2(b) F^2/2k(c) 2k/T^2(d) F^2/2dI had been asked this question in final exam.This is a very interesting question from The Potential Energy of a Spring in chapter Work, Energy and Power of Physics – Class 11

Answer»

Correct answer is (b) F^2/2k

For EXPLANATION I WOULD SAY: F = k*d

PE = 1/2*k*d^2

 = 1/2*F*d

 = 1/2*F*F/k

 = F^2/2k.



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