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Assuming 1 metric ton of coal gives heat of combustion equal to 8 kcal and a single fission of `.^(235)U` releases 200 MeV. Calculate the minimum consumption in kg of `.^(235)U` to be heat equivalent ot 100 ton of coal |
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Answer» Correct Answer - `[M = 4.077 xx 10^(-8) kg]` |
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