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At `10^(@)C`, the osmotic pressure of urea solution is `500 mm`.The solution is diluted and the temperature is raised to `25^(@)C`.when the osmotic pressure is found to be `105.3 mm`. Determine the extent of dilution. |
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Answer» For initial solution,`pi=500/760`atm,`T=283 K` Using `piV=nRT rArr 500/760xx(V_(1))=nxxRxx283` …(i) After dilution, let volume becomes `V_(2)` and temperature is raised to `25^(@)C,i.e., 298 K`. `pi=105.3/760`atm `105.3/760xx(V_(2))=nxxRxx298` ...(ii) `:.` By Eqs.(i) and Eqs.(ii), we get `V_(1)/V_(2)=(283)/(298)xx(105.3)/(500)` `V_(1)/V_(2)=1/5 rArr V_(2)=5V_(1)` i.e., the solution was diluted to 5 times. |
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