InterviewSolution
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InterviewSolution
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At `25^(@)C, 1 mol` of A having a vapour pressure of 100 torr and 1 mole of B having a vapour pressure of 300 torr were mixed. The vapour at equilibrium is removed, condensed and the condensate is heated back to `25^(@)C`. The vapour now formed are again removed, recondensed and analyzed. what is the mole fraction of A in this condensate? |
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Answer» Correct Answer - `0.1` `P_(A)^(@) = 100, P_(B)^(@) = 300, X_(A) = X_(B) = (1)/(2)` `P_(T) = 200` `Y_(A) = (100 xx(1)/(2))/(200) =(1)/(4)` On condensation `X_(A) = (1)/(4),X_(B) = (3)/(4)` `P_(T) = 100 xx (1)/(4) +300 xx (3)/(4) = 250` `Y_(A) = (25)/(250) = 0.1` on further condensation `X_(A) = 0.1` |
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