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At 25°C, 3g of a solute A in 100 ml of an aqueous solution gave an osmotic pressure of 2.5 atm. What is the nature of the solute (associated or dissociated) if its normal molar mass is 246? |
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Answer» Л = i x C x R x T 2.5 = i x ( 3/246) x ( 0.0821 / 0.1) x 298 i = 2.01 As i > 1 the solute A undergoes dissociation. |
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