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At `298 K` , the vapour pressure of water is `23.75 mm Hg`. Calculate the vapour pressure at the same temperature over `5%` aqueous solution of urea. `[CO(NH_(2))_(2)]`. |
Answer» Appling Raoult,s law `(P^(@)-P_(s))/P^(@)=n_(2)/n_(1)=(W_(2)//Mw_(2))/(W_(1)//Mw_(1))=(W_(2)xxMw_(2))/(Mw_(1)xxW_(1))` Substituting the values, we get `(23.75-P_(s))/23.75 =5/60xx18/95` `23.75-P_(s)=5/60 xx18/95xx23.75 ` or `23.75-P_(s)=0.375 rArr P_(s)=23.375 mm` |
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