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At `40^(@)C`, vapour pressure in Torr of methanol nd ethanol solution is `P=119x+135` where `x` is the mole fraction of methanol. HenceA. vapour pressure of pure methanol is `119` TorrB. vapour pressure of pure ethanol is `135` TorrC. vapour pressure of equimolar mixture of each is `127` TorrD. mixture is completely immiscible |
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Answer» `P=119x+135` `x=1` for pure methanol. so `P^(@)_("methanol")=119+135=254` Torr But for pure ethanol `x=0` so `P_("ethanol")^(@)=135` Torr |
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