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At a given instant there are `25%` undecayed ratio-activity nuclei in sample. After `10` second, the number of undecyed nuclei reduces to `12.5%`. Calculate (a) mean-life of the nuclei and (a) the time in which the number undecayed nuclei will further reduce to `6.25%` of the reduced number. |
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Answer» (a) Half-like `T_(1//2) = 10 sec` Meanlife `bar(T) = 1.44T_(1//2) = 1.44 xx 10 = 1.44 sec` (b) `(N_(0))/(4) overset(T_(1//2))rarr(N_(0))/(8)overset(T_(1//2))rarr(N_(0))/(16)` `t = T_(1//2) = 10 sec` |
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