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At a particular temperature, the vapour pressure of two liquids A and B are 120 and 180 mm of Hg respectively. Two moles of A and 3 Moles of B are mixed to form an ideal solution. What is the vapour pressure for the solution? |
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Answer» P°A = 120mm of Hg P°B = 180 mm of Hg XA = 2/5 XB = 3/5 PA = P°A x XA = 120 × 2/5 = 48 mm of Hg PB = P°B x XB = 180 × 3/5 = 108 mm of Hg PS = PA + PB = 108 + 48 = 156 mm of Hg |
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