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At what angle of projectile (θ) is the horizontal range minimum?(a) θ = 45°(b) θ = 60°(c) θ = 90°(d) θ = 75°The question was asked in quiz.The question is from Simple Projectile Motion topic in division Motion in a Plane of Physics – Class 11

Answer»

Correct choice is (c) θ = 90°

Explanation: The formula for horizontal range is R = v^2 (sin 2θ)/g. When θ = 90°, sin 2θ = sin 180° = 0. HENCE, the range covered BECOMES 0. Since range cannot be negative, 0 is the minimum VALUE it can attain.



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