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At what frequency will the current lead the voltage by 30° in a series circuit with R = 10Ω and C = 25 μF?(a) 11.4 kHz(b) 4.5 kHz(c) 1.1 kHz(d) 24.74 kHzI had been asked this question during an internship interview.My question is based upon Problems of Series Resonance Involving Frequency Response of Series Resonant Circuit topic in chapter Resonance & Magnetically Coupled Circuit of Network Theory

Answer»

Right choice is (a) 11.4 kHz

The explanation: From the IMPEDANCE diagram, 10 – jXC = Z∠-30°

∴ – XC = 10 TAN (-30°) = -5.77 Ω

∴ XC = 5.77 Ω

Then, XC = \(\frac{1}{2πfC}\) or, f = \(\frac{1}{2πX_C C}\) = 1103 HZ = 1.1 kHz.



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