At what height above the surface of the earth, the acceleration due to the gravity of the earth becomes 5% of that of the surface?(a) h = 0.5 R(b) h = 1.5 R(c) h = 2.5 R(d) h = 3.5 RThe question was asked in my homework.The origin of the question is Acceleration due to Gravity below and above the Surface of Earth topic in portion Gravitation of Physics – Class 11

At what height above the surface of the earth, the acceleration due to

1.	At what height above the surface of the earth, the acceleration due to the gravity of the earth becomes 5% of that of the surface?(a) h = 0.5 R(b) h = 1.5 R(c) h = 2.5 R(d) h = 3.5 RThe question was asked in my homework.The origin of the question is Acceleration due to Gravity below and above the Surface of Earth topic in portion Gravitation of Physics – Class 11
Answer» Right ANSWER is (d) H = 3.5 R To explain I would SAY: Acceleration due to gravity on the surface of the earth; g = (GM1)/R^2 Acceleration due to gravity above the surface of the earth; g’ = (GM1)/(R + h)^2 g’ = (5/100) x g (GM1)/(R + h)^2 = (5/100) x (GM1)/R^2 R^2 x 100 = (R + h)^2 x 5 Taking square root on both sides; R x 10 = (R + h) x 2.24 7.76 x R = 2.24 x h h = 3.5 x R.

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