At what height from the center of the Earth the acceleration due to gravity will be 1/4th of its value as at the earth.

At what height from the center of the Earth the acceleration due to gr

1.	At what height from the center of the Earth the acceleration due to gravity will be 1/4th of its value as at the earth.
Answer» Solution :Given: Height from the CENTRE of the Earth, R. =R+h The acceleration DUE to gravity at that height, g. = `g//4` Formula: g=`(GM)/(R^(2))` `(g)/(g)=((R)/(R))^(2)` =`((R+h)/(R))^(2)=[(R)/(R)+(h)/(R)]^(2)` =`[1+(h)/(R)]^(2)` 4=`[1+(h)/(R)]^(2)` Apply root on both sides `2=[1+(h)/(R)]` orh=R R’=2R From the centre of the Earth, the object is placed at twice the radius of the earth (ii)" How many electrons are passing PER second in a circuit in which there is a current of 5A." "Current I = 5A Timet - 1 second" "Charge of electron (e) = `1.6xx10^(-19)C` I=`(q)/(t)=(ne)/(t)`" "Number of electron", n =`(It)/(e)` =`(5xx1)/(1.6xx10^(-19))` n=`3.125xx10^(19)`