1.

At what temperature the value of celcius and fahrenheit scale concid.

Answer»

Solution :Let `T_(C)=T_(F)=X`
`(T_(C)=0)/(100)=(T_(F)-32)/(180)`
`(x)/(100)=(x-32)/(180)`
`100x-3200=180 x`
`-80x=3200`
`x=(-3200)/(80)`
`=-x-40^(@)`


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