1.

Atomic weight of ` Ne` is ` 20.2 Ne` is a mixuture of ` Ne^(20)` and ` Ne^(22)`. Relative abunduance fo heavior isotope is :A. ` 90`B. `20`C. `40`D. `10`

Answer» Correct Answer - D
Average isotopc wt `= sum % x ` isopopic wt .
` (% xx "wt. of isopope "+ % xx "wt . Of other isopope")/( 100)`
`therefore 20. 2 = ( a xx 20 + ( 100 -a) xx 22)/( 100)`
`therefore A = 90`,
per cent fo lighter isopope ` = 100 - 90 =10`.


Discussion

No Comment Found

Related InterviewSolutions