Atomic weight of Th is 232 and its atomic number is 90. The number of `alpha`- and `beta`-particles which be lost so that an isotope of lead (atomic weight 208 and atomic number 82) is produced isA. `4 alpha + 6 beta`B. `6 alpha + 4 beta`C. `8 alpha + 2 beta`D. `10 alpha + 2 beta`

Atomic weight of Th is 232 and its atomic number is 90. The number of

1.	Atomic weight of Th is 232 and its atomic number is 90. The number of `alpha`- and `beta`-particles which be lost so that an isotope of lead (atomic weight 208 and atomic number 82) is produced isA. `4 alpha + 6 beta`B. `6 alpha + 4 beta`C. `8 alpha + 2 beta`D. `10 alpha + 2 beta`
Answer» Correct Answer - B Let the reaction emits `x alpha`-particles and `y beta`-particle `._(90)Th^(232) rarr x ._(2)He^(4) + y ._(-1)e^(0) + ._(82)Pb^(208)` Equating atomic mass number on both sides `232 = 4x + y (0) + 208` `:.x = (232 - 208)/(4) = (24)/(4) = 6` `:. alpha`-particles emitted = 6 Equating atomic number on both sides `90 = 82 + 6 xx 2 + y (-1)` `:. y = 94 - 90 = 4` `:. beta`-particle emitted = 4

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Atomic weight of Th is 232 and its atomic number is 90. The number of `alpha`- and `beta`-particles which be lost so that an isotope of lead (atomic weight 208 and atomic number 82) is produced isA. `4 alpha + 6 beta`B. `6 alpha + 4 beta`C. `8 alpha + 2 beta`D. `10 alpha + 2 beta`

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