1.

`ax^2+2hxy+by^2+2gx+2fy+c=0`

Answer» Given: `ax^(2)+2hxy+by^(2)+2gx+2fy+c=0." …(i)"`
Differentiating both sides of (i) w.r.t. x, we get
`2ax+2h(x.(dy)/(dx)+y.1)+2by.(dy)/(dx)+2g+2f.(dy)/(dx)=0`
`rArr(2ax+2hy+2g)+(2hx+2by+2f).(dy)/(dx)=0`
`rArr (dy)/(dx)=-((ax+hy+g)/(hx+by+f)).`


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