

InterviewSolution
Saved Bookmarks
1. |
`ax^2+2hxy+by^2+2gx+2fy+c=0` |
Answer» Given: `ax^(2)+2hxy+by^(2)+2gx+2fy+c=0." …(i)"` Differentiating both sides of (i) w.r.t. x, we get `2ax+2h(x.(dy)/(dx)+y.1)+2by.(dy)/(dx)+2g+2f.(dy)/(dx)=0` `rArr(2ax+2hy+2g)+(2hx+2by+2f).(dy)/(dx)=0` `rArr (dy)/(dx)=-((ax+hy+g)/(hx+by+f)).` |
|