1.

Based on solute-solvent interactions, arrange the following in order of increasing solubility in n*octane and explain. Cyclohexane, KCl, CH3OH, CH3CN.

Answer»

(i) Cyclohexane and n-octane both are non-polar. Hence they mix completely in all proportions. 

(ii) KCl is an ionic compound while n-octane is nonpolar. Hence, KCl will not dissolve at all in n-octane. 

(iii) CH3OH and CH3CN both are polar but CH3CN is less polar than CH3OH. As the solvent is non-polar, CH3CN will dissolve more than CH3OH is n-octane. 

Thus the order of solubility will be KCl< CH3OH < CH3CN < Cyclohexane.



Discussion

No Comment Found

Related InterviewSolutions