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Based on solute-solvent interactions, arrange the following in order of increasing solubility in n*octane and explain. Cyclohexane, KCl, CH3OH, CH3CN. |
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Answer» (i) Cyclohexane and n-octane both are non-polar. Hence they mix completely in all proportions. (ii) KCl is an ionic compound while n-octane is nonpolar. Hence, KCl will not dissolve at all in n-octane. (iii) CH3OH and CH3CN both are polar but CH3CN is less polar than CH3OH. As the solvent is non-polar, CH3CN will dissolve more than CH3OH is n-octane. Thus the order of solubility will be KCl< CH3OH < CH3CN < Cyclohexane. |
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