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Benzene and toluene form two ideal solution A and B at 313 K, Solution A(total pressure `"P"_("A")`) contains equal mole fo toluene and benzene. Solution B contains equal masse of both(total pressure `"P"_("B")`). The vapour pressure of benzene and toluene are 160 and 60 mm of Hg respectively at 313 K. Calculate the value of `"P"_("A")//"P"_(B")`. |
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Answer» Correct Answer - 0.964 Benzene-B, Toluene-T `"P"_("A")="X"_("B")"P"_("B")^(0)+X_("T")"P"_("T")^(0)` `"n"_("B")="n"_("T")="n"` `"P"_("solution")=("n")/(2"n")xx160+("n")/(2"n")xx60` `"P"_("solution")=110"mm Hg"` Now for solution B `"w"_("B")="w"_("T")="w"` `"X"_("b")=(("w")/(78))/(("w")/(78)+("w")/(92)),"X"_("t")=1-(46)/(85)` `=(92)/(170)" "=(39)/(85)` `=(46)/(86)` `"P"_("solution")^(1)="X"_("b")"P"_("b")^(0)+"X"_("t")"P"_("t")^(0)` `46/85xx160+39/85xx60=1940/17` |
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