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Binding energy per nucleon of fixed nucleus `X^(A)` is `6 MeV`. It absorbs a neutron moving with `KE= 2 MeV` and converts into Y at ground state, emitting a photon of energy `1 MeV`. The Binding energy per nucleon of Y (in MeV) is -A. `((6A+1))/((A+1))`B. `((6A-1))/((A+1))`C. `7`D. `(7)/(6)` |
Answer» Correct Answer - B `BE` of `X=6A` `BE` of `Y=6A-2+1=6A-1` [Because absorption of energy decreases `BE` and releas of energy increases `BE`] `:. (BE)/("nucleon")=(6A-1)/(A+1)` |
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