1.

Boron naturally occurs as a mixture of boron - 10 ("5 protons "+" 5 neutrons") and boron11 ("5 protons "+" 6 neutrons") isotopes. The percentage abundance of B-10 is 20 and that of B-11 is 80. Then, the atomic mass of boron in calculated as follows :

Answer»

SOLUTION :`"Atomic mass of BORON "=(10xx(20)/(100))+(11xx(80)/(100))`
`=(10xx0.20)+(11xx0.80)`
`=2+8.8="10.8 amu"`


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