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Buses start from a bus terminal with a speed of 40 km/hr, at intervals of 5 minutes What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 4 minutes |
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Answer» Here, distance travelled by the bus in `5` minutes will be equal to the sum of the distance covered by the bus and the man in `4` minutes. Let speed of the man is `x` km/h.Then, `40**5/60 = 40**4/60+x**4/60` `=>10/3 = 8/3+x/15` `=>2/3 = x/15` `=>x = 10` So, the speed of the man is `10` km/h. |
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