1.

CaCO_3 + 2HCl to CaCl_2 + H_2O + CO_2 The mass of calcium chloride formed when 2.5 g calcium carbonate are dissolved in excess of hydrochloric acid is

Answer»

1.39g
2.78g
5.18g
17.8g

Solution :`CaCO_3 + 2HCl to CaCl_2+ H_2O + CO_2`
`100G CaCO_3 ` GIVEN 111g `CaCl_2`
`THEREFORE 2.5g CaCO_3` given`111/100 XX 2.5`
` = 2.78 G CaCl_2`


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