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`CaCO_(3)(s) hArr CaO(s)+CO_(2)(g)` For the equilibrium , it is found that `log K_(p)=8-(6400(K))/(T)` `T=527^(@)C` if `:`A. `K_(p)=7.2 xx 10^(-5)`B. `K_(p)=1`C. `K_(p)=13.04 xx 10^(3)`D. `K_(p)=10`. |
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Answer» Correct Answer - B `=T=527^(@)C=527+273=800K` `:. logK_(p)=8-(6400K)/(T)` `=8-(6400)/(800)=8-8=0` `log K_(p)=0` `:. K_(p)=1` |
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