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Calculate energy of electron which is moving in the orbit that has its radius , sixteen times the radius of first Bohr orbit for H-atom.

Answer» Correct Answer - `-136xx10^(-19)` Joules
Radius `=16(RH)=16xx0.0529`
`16xx0529=0.0529xx(n^(2))/(Z)`
`16=(n^(2))/(1)" "n=4`
`T.E.=-13.6xx(n^(2))/(Z^(2))l.v=0.85l.v=-1.36xx10^(-19)J`


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