Calculate enthalpy change for the process C Cl_(4) (g) rarr C(g) + 4Cl(g) and calculate Bond enthalpy of C-Cl bond in C Cl_(4) Given: Delta_("vap") H^(theta) = 30.5kJ mol^(-1), Delta_(f) H^(theta) (C Cl_(4)) = - 135.5 kJ mol^(-1), Delta_(a) H^(theta)(C ) = 715kJ mol^(-1) and Delta_(a) H^(theta) (Cl_(2)) = 242 kJ mol^(-1)

Calculate enthalpy change for the process C Cl_(4) (g) rarr C(g) + 4Cl

1.	Calculate enthalpy change for the process C Cl_(4) (g) rarr C(g) + 4Cl(g) and calculate Bond enthalpy of C-Cl bond in C Cl_(4) Given: Delta_("vap") H^(theta) = 30.5kJ mol^(-1), Delta_(f) H^(theta) (C Cl_(4)) = - 135.5 kJ mol^(-1), Delta_(a) H^(theta)(C ) = 715kJ mol^(-1) and Delta_(a) H^(theta) (Cl_(2)) = 242 kJ mol^(-1)
Answer» SOLUTION :`326 KJ MOL^(-1)`