1.

Calculate K_(p) for the following reaction if partial pressures of NH_(3), N_(2) and H_(2) are 0.4,0.3,0.2, atm, respectively. 2NH_(3) hArr N_(2)+3H_(2)

Answer»

SOLUTION :`K_(p)=(p^(3)H_(2).pH_(2))/(P^(2)NH_(2))`
`K_(p)=((0.2)^(3)*(0.3)("atm")^(4))/((0.4)^(2)("atm")^(2))`
`K_(p)=0.015 "atm"^(2)`


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