1.

Calculate maximum power of accomodation of a person having normal vision.

Answer»

Solution :For a PERSON having normal vision, least distance of DISTINCT vision d = 25 CM = 0.25 m.
So, maximum power of accomodation,
`P = (1)/(f("in mm")) = (1)/(d) = (1)/(0.25) = 4D`


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