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Calculate mole fraction of ethyl alcohol and water in a solution containing 46 g ethyl and 36g water. |
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Answer» `n_(C_(2)H_(5)OH)=(46)/(46)=1` `n_(H_(2)O)=(36)/(18)=2` `X_(C_(2)H_(5)OH)=(n_(C_(2)H_(5)OH))/(n_(C_(2)H_(5)OH))=(1)/(1+2)=(1)/(3)` `X_(H_(2)O)=1-(1)/(3)=(2)/(3)` |
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