

InterviewSolution
Saved Bookmarks
1. |
Calculate normality of the mixure obtained by mixing `100ml` of `0.1N HCL` and `50 ml` of `0.25N NaOH` solutionA. ` 0.0467 N `B. ` 0.0367 N `C. ` 0.0267N `D. ` 0.0167N ` |
Answer» Correct Answer - D Meq.of HCl=`100xx0.1=10` Meq. of NaOH=`50xx0.25=1.25` `:.`HCl and NaOH neturalized each other with equal. Eq. Meq. Of NaOH left=`12.5-10=2.5` Volume of new solution =`100+50=150ml.` `N_(NAOH)`left=`(2.5)/(150)=0.0167N` Hence normality of the mixture obtained is `0.0167N` |
|