1.

Calculate normality of the mixure obtained by mixing `100ml` of `0.1N HCL` and `50 ml` of `0.25N NaOH` solutionA. ` 0.0467 N `B. ` 0.0367 N `C. ` 0.0267N `D. ` 0.0167N `

Answer» Correct Answer - D
Meq.of HCl=`100xx0.1=10`
Meq. of NaOH=`50xx0.25=1.25`
`:.`HCl and NaOH neturalized each other with equal. Eq.
Meq. Of NaOH
left=`12.5-10=2.5`
Volume of new solution =`100+50=150ml.`
`N_(NAOH)`left=`(2.5)/(150)=0.0167N`
Hence normality of the mixture obtained is `0.0167N`


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