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Calculate osmotic pressure of a solution obtained by mixing `100 mL` of `3.4%` solution "(weight/volume)" of urea "(molecular weight 60)" and `100 mL` of `1.6%` solution "(weight/volume)" of cane sugar "(molecular weight 342)" at `20^(@)C`. |
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Answer» No. of moles of urea `= (3.4)/(60)=0.0567` No. of moles of can sugar `=(1.6)/(342)=0.0047` Total number of moles `=(0.0567+0.0047)=0.0614` Total volume of solution `= (100+100)=200` mL `=0.1` litre PV = (Total number of moles) `xx S xx T` `P=(0.0614)/(0.2)xx0.0821xx293=7.385`atm. |
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