1.

Calculate the amount of heat energy to be supplied to convert 4 kg of ice at 0^@C completely into water at0^@C if latent heat of fusion for ice is 80 cal/g.

Answer»


Solution :Given Mass (m) `=4 kg =4 xx 10^3 g`, latent
heat of fusion for ICE (L) = 80 cal /g .
To find ,Heat energy (Q)
Formula :Q=mL
Calculation: Formula formula,
`Q= 4 xx 10^3 xx 80 = 320000 cal `
= 320 kcal .


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