1.

Calculate the amount of heat generated while transferring 90000 coulombs of charge between the two terminals of a battery of 40 V in one hour. Also determine the power expended in the process.

Answer»

Solution :Q = 90000 t= 1 h = 3600 s V = 40 V
`I = (Q)/(t) = (90,000)/(3600) = 25 `A
`R= (V)/(I) =(40)/(25) = 1.6 Omega`
`H= I^(2) Rt = 25 xx25xx1.6xx 3600`
`=36xx10^(5) H or 3600 kJ`
`P =I^(2)R = 25 xx25xx1.6 `
= 1000 W = 1 KW.


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