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Calculate the amount of heat generated while transferring 90000 coulombs of charge between the two terminals of a battery of 40V in one hour. Also determine the power expended in the process. |
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Answer» Solution :Here charge transferred Q=90000C, potential DIFFERENCE between the terminals of battery V=40V and time t=1 h =3600s. `THEREFORE` CURRENT `I=Q/t=90000/3600=2A` , `therefore ` Amount of heat generated `H=Vlt=40 TIMES 25 times 3600=3600000J=3.6 times 10^6 J` and POWER expended `P=H/t=VI=40 times 25=1000W` |
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