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Calculate the amount of heat required to convert 5 g of ice of 0 °C into water at 0 °C. (Specific latent heat of fusion of ice = 80 cal/g) |
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Answer» Here, m = 5 g, L = 80 cal/g; Q = ? Amount of heat required, Q = mL = 5 g × 80 cal/g = 400 calories. |
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