1.

Calculate the amount of KCl which must be added to 1Kg of water so that the freezing point is depressed by 2 kelvin. (Kf for water = 1.86 K Kg mol-1)

Answer»

ΔT = i X Kf X m

2 = 2 X 1.86 X ( n/1)

N = 1/ 1.86

= 0.537 mol



Discussion

No Comment Found

Related InterviewSolutions