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Calculate the amount of KCl which must be added to 1Kg of water so that the freezing point is depressed by 2 kelvin. (Kf for water = 1.86 K Kg mol-1) |
Answer» ΔTf = i X Kf X m 2 = 2 X 1.86 X ( n/1) N = 1/ 1.86 = 0.537 mol |
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