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Calculate the amount of oxalic acid `(H_(2)C_(2)O_(4).2H_(2)O)` required to obtain `250m` of deci-molar solution.A. 15.75gB. 1.575gC. 157.5gD. None |
Answer» Correct Answer - A Molarity of solution`=0.5"M"` Volume of solution`=250ml` `therefore` mili mole oxalic acid`="M"xx"V"(ml)=1/2xx250 " or ""w"/"M"xx1000=0.5xx250` `therefore" w"=(250xx126)/2xx1000=15.76"g"` |
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