1.

Calculate the amount of sodium oxide formed when 2.3 g of sodium reacts with 3.2 g of oxygen.

Answer»

Solution :`{:(4Na+O_(2) to 2Na_(2)O),("4 moles" " 1 MOLE" " 2 moles"):}`
`4 xx 23` g of sodium reacts with 32 g of `O_(2)`
2.3g of sodium reacts with =`(2.3 xx 32)/(4 xx 23) = 0.8` g
As the amount of oxygen PRESENT is 3.2 g, all the oxygen is not utilised for FORMATION of sodium oxide. The amount of sodium oxide formed is determined by sodium.`4 xx 23` g of sodium PRODUCES `2 xx 62` g of sodium oxide.
2.3 g of sodium produces = `(2.3 xx 2 xx62)/(4 xx 23) = 3.1` g
Amount of sodium oxide formed = 3.1 g.


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