Calculate the biling point of a solution containing 0.456 g of comphor (molar mass=152 g mol^(-1)) dossoved in 31.4 g of acetone(b.p.= 329.45 K). Given that the molecular elevation constant per 100 g of solvent is 17.2 K.

Calculate the biling point of a solution containing 0.456 g of comphor

1.	Calculate the biling point of a solution containing 0.456 g of comphor (molar mass=152 g mol^(-1)) dossoved in 31.4 g of acetone(b.p.= 329.45 K). Given that the molecular elevation constant per 100 g of solvent is 17.2 K.
Answer» Calculation of elevaltion in boiling point `(T_(b))`. `DeltaT_(b)=(K_(b)xxW_(B))/(M_(B)xxW_(A))` Mass of camphor `(W_(B))=0456 g` Mass of acetone `(W_(A))`=31.4 g= 0.0314 kg `" Molal elevation contant "(K_(b))=(17.2K per 100 g)/1000=1.72 "K kg mol"^(-1)` `" Molar mass of camphor "(M_(B))=152 g mol^(-1))` `DeltaT_(b)=((1.72 K kg mol^(-1))xx(0.456 g))/((152 g mol^(-1))xx(0.0314 kg))=0.164 K` Calculation of boiling point of solution. Boiling point of acetone= 329.45 K Elevation in b.p tempertaure=0.164 K Boiling point of solution=329.45K+0.164 K= 329.614 K

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Calculate the biling point of a solution containing 0.456 g of comphor (molar mass=152 g mol^(-1)) dossoved in 31.4 g of acetone(b.p.= 329.45 K). Given that the molecular elevation constant per 100 g of solvent is 17.2 K.

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