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Calculate the binding energy of the oxygen isotope `._(8)^(16)O`. The mass of the isotope is 16.0 amu. (Given e=0.0005486 amu, p=1.00757 amu and n=1.00893 amu). |
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Answer» The isotope `._(8)^(16)O` contains 8 protons, 8 neutrons and 8 electrons. Actual mass of the nucleus of `._(8)^(16)O` `=16-`mass of 8 electrons `=16-8xx0.0005486=15.9956`amu Mass of the nucleus of `._(8)^(16)O` =Mass of 8 protons + Mass of 8 neutrons `=8xx1.00757+8xx1.00893=16.132`amu Mass defect `=(16.132-15.9956)=0.1364` amu Binding energy `=0.1364xx931=127`MeV |
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