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Calculate the current flowing through a wire ofresistance 7.5 Omega connected to a battery of potentialdifference 1.5. V. |
Answer» Solution :Given: `R = 7.5 OMEGA, V = 1.5 V` From Ohm.s law, `V = IR` CURRENT in wire `I = (V)/(R) = (1.5)/(7.5) = 0.2 A` |
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