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Calculate the current in bracnhes containing `R_1, R_2 and R_3` in the circuit shown in |
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Answer» Potential difference across `R_1and R_3` is independent of time and remains constant. So current in them remains constant. Veriation in current will occur only in `R_2`. So `i_1 =(V)/(R_1) = constant, i_2 = i_0e^(-t//R_2C)` where `i_0 = (V)/(R_2) and i_3 = (v)/(R_3)` |
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