InterviewSolution
Saved Bookmarks
| 1. |
Calculate the de Broglie wavelength for a beam of electron whose energy is `100 eV` |
|
Answer» Correct Answer - A::B::C::D `E = (1)/(2) mv^(2) = 100 eV = 100 xx 1.6 xx 10^(-19) J` `v^(2)= (2E)/(m)` `v = ((2E)/(m))^(1//2)` `lambda = ((2E)/(m))^(1//2) = sqrt(2mE)` `lambda = (h)/(mv) = (h)/(sqrt(2mE)0) meter ` `lambda = (6.6 xx 10^(-34))/((2 xx 9.1 xx 10^(-31) xx 100 xx 1.6 xx 10^(-19))^(1//2))` `= 1.23 xx 10^(-10) m = 1.23 Å` |
|