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Calculate the drift speed of electrons in copper wire carrying acurrent of 1A and cross sectional area 10^(-6)m^(2). |
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Answer» Solution :Current I = 1 A Cross sectional area `A=10^(-6)m^(2)` The electron density of COPPER `'n'=8.5xx10^(28)m^(-3)("Experimentally FOUND")` Magnitude of electric charge `'e'=1.602xx10^(-19)C=q` `"Drift speed"(v_(d))=(I)/(nqA)=(1)/(8.510^(28)xx1.602xx10^(-19)xx10^(-6))=(1)/(13.617xx10^(3))=0.07mm//sec` |
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