1.

Calculate the energy associated with photon of light having a wavelength 6000Ã…. [`h=6.624xx10^(-27)erg-sec`.]

Answer» We know that `E=hv=h.(c)/(lamda)` ltBrgt `h=6.624xx10^(-27)erg-sec,c=3xx10^(10)cm//sec`
So, `E=((6.624xx10^(-27))xx(3xx10^(10)))/(6xx10^(-5))=3.312xx10^(-12)erg`.


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