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Calculate the energy in kilocalorie per mol of the photons of an electromagnetic radiation of wavelength 7600Ã…. |
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Answer» `lamda=6000` Ã…`=7600xx10^(-8)cm` `c=3xx10^(10)cms^(-1)` Frequency, `v=(c)/(lamda)=(3xx10^(10))/(7600xx10^(-8))=3.947xx10^(14)s^(-1)` Energy of one photon `=hv=6.61xx10^(-12)xx6.02xx10^(23)` `=15.71xx10^(11)erg` Energy of one mole of photos in kilocalorie. `=(15.71xx10^(11))/(4.185xx10^(10))" "[1kcal=4.185xx10^(10)erg]` `=37.538` kcal per mol. |
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