1.

Calculate the energy in kilocalorie per mol of the photons of an electromagnetic radiation of wavelength 7600Ã….

Answer» `lamda=6000` Ã…`=7600xx10^(-8)cm`
`c=3xx10^(10)cms^(-1)`
Frequency, `v=(c)/(lamda)=(3xx10^(10))/(7600xx10^(-8))=3.947xx10^(14)s^(-1)`
Energy of one photon `=hv=6.61xx10^(-12)xx6.02xx10^(23)`
`=15.71xx10^(11)erg`
Energy of one mole of photos in kilocalorie.
`=(15.71xx10^(11))/(4.185xx10^(10))" "[1kcal=4.185xx10^(10)erg]`
`=37.538` kcal per mol.


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